# How do you find the vertex and intercepts for #y^2=1/3x#?

##### 2 Answers

#### Explanation:

For

Therefore

Therefore

Therefore there is no real vertex:

graph{sqrt(1/3x) [-10, 10, -5, 5]}

The vertex and intercepts are all at

#### Explanation:

If

If

So the only

Both positive and negative values are possible for

graph{y^2=x/3 [-5.22, 12.56, -4.484, 4.405]}